2x+7/3-2(x^-4)/5x-4x^-6/15x=7x^+6/3x^

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Solution for 2x+7/3-2(x^-4)/5x-4x^-6/15x=7x^+6/3x^ equation: 



2x+7/3-2(x^-4)/5x-4x^-6/15x=7x^+6/3x^

We move all terms to the left:

2x+7/3-2(x^-4)/5x-4x^-6/15x-(7x^+6/3x^)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R





Domain of the equation: 15x!=0

x!=0/15

x!=0

x∈R





Domain of the equation: 3x^)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-2x-2(x^-4)/5x-6/15x-(7x^+6/3x^)+7/3=0

We get rid of parentheses

-2x-2(x^-4)/5x-6/15x-7x^-6/3x^+7/3=0

We calculate fractions

We do not support expression: x^3

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